Optimal. Leaf size=132 \[ -\frac{d x \left (d^2-e^2 x^2\right )^{3/2}}{4 e^2}-\frac{d^2 \left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}+\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 e^3}+\frac{d^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{8 e^3}+\frac{d^3 x \sqrt{d^2-e^2 x^2}}{8 e^2} \]
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Rubi [A] time = 0.20001, antiderivative size = 132, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 5, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2 \[ -\frac{d x \left (d^2-e^2 x^2\right )^{3/2}}{4 e^2}-\frac{d^2 \left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}+\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 e^3}+\frac{d^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{8 e^3}+\frac{d^3 x \sqrt{d^2-e^2 x^2}}{8 e^2} \]
Antiderivative was successfully verified.
[In] Int[x^2*(d + e*x)*Sqrt[d^2 - e^2*x^2],x]
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Rubi in Sympy [A] time = 31.8788, size = 112, normalized size = 0.85 \[ \frac{d^{5} \operatorname{atan}{\left (\frac{e x}{\sqrt{d^{2} - e^{2} x^{2}}} \right )}}{8 e^{3}} + \frac{d^{3} x \sqrt{d^{2} - e^{2} x^{2}}}{8 e^{2}} - \frac{d^{2} \left (d^{2} - e^{2} x^{2}\right )^{\frac{3}{2}}}{3 e^{3}} - \frac{d x \left (d^{2} - e^{2} x^{2}\right )^{\frac{3}{2}}}{4 e^{2}} + \frac{\left (d^{2} - e^{2} x^{2}\right )^{\frac{5}{2}}}{5 e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**2*(e*x+d)*(-e**2*x**2+d**2)**(1/2),x)
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Mathematica [A] time = 0.0862242, size = 91, normalized size = 0.69 \[ \frac{15 d^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )+\sqrt{d^2-e^2 x^2} \left (-16 d^4-15 d^3 e x-8 d^2 e^2 x^2+30 d e^3 x^3+24 e^4 x^4\right )}{120 e^3} \]
Antiderivative was successfully verified.
[In] Integrate[x^2*(d + e*x)*Sqrt[d^2 - e^2*x^2],x]
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Maple [A] time = 0.057, size = 125, normalized size = 1. \[ -{\frac{dx}{4\,{e}^{2}} \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{{d}^{3}x}{8\,{e}^{2}}\sqrt{-{e}^{2}{x}^{2}+{d}^{2}}}+{\frac{{d}^{5}}{8\,{e}^{2}}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{e}^{2}{x}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-{\frac{{x}^{2}}{5\,e} \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}-{\frac{2\,{d}^{2}}{15\,{e}^{3}} \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^2*(e*x+d)*(-e^2*x^2+d^2)^(1/2),x)
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Maxima [A] time = 0.81739, size = 158, normalized size = 1.2 \[ \frac{d^{5} \arcsin \left (\frac{e^{2} x}{\sqrt{d^{2} e^{2}}}\right )}{8 \, \sqrt{e^{2}} e^{2}} + \frac{\sqrt{-e^{2} x^{2} + d^{2}} d^{3} x}{8 \, e^{2}} - \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac{3}{2}} x^{2}}{5 \, e} - \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac{3}{2}} d x}{4 \, e^{2}} - \frac{2 \,{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac{3}{2}} d^{2}}{15 \, e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(-e^2*x^2 + d^2)*(e*x + d)*x^2,x, algorithm="maxima")
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Fricas [A] time = 0.278723, size = 479, normalized size = 3.63 \[ \frac{24 \, e^{10} x^{10} + 30 \, d e^{9} x^{9} - 320 \, d^{2} e^{8} x^{8} - 405 \, d^{3} e^{7} x^{7} + 760 \, d^{4} e^{6} x^{6} + 1035 \, d^{5} e^{5} x^{5} - 480 \, d^{6} e^{4} x^{4} - 900 \, d^{7} e^{3} x^{3} + 240 \, d^{9} e x - 30 \,{\left (5 \, d^{6} e^{4} x^{4} - 20 \, d^{8} e^{2} x^{2} + 16 \, d^{10} -{\left (d^{5} e^{4} x^{4} - 12 \, d^{7} e^{2} x^{2} + 16 \, d^{9}\right )} \sqrt{-e^{2} x^{2} + d^{2}}\right )} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) + 5 \,{\left (24 \, d e^{8} x^{8} + 30 \, d^{2} e^{7} x^{7} - 104 \, d^{3} e^{6} x^{6} - 135 \, d^{4} e^{5} x^{5} + 96 \, d^{5} e^{4} x^{4} + 156 \, d^{6} e^{3} x^{3} - 48 \, d^{8} e x\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{120 \,{\left (5 \, d e^{7} x^{4} - 20 \, d^{3} e^{5} x^{2} + 16 \, d^{5} e^{3} -{\left (e^{7} x^{4} - 12 \, d^{2} e^{5} x^{2} + 16 \, d^{4} e^{3}\right )} \sqrt{-e^{2} x^{2} + d^{2}}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(-e^2*x^2 + d^2)*(e*x + d)*x^2,x, algorithm="fricas")
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Sympy [A] time = 14.6335, size = 279, normalized size = 2.11 \[ d \left (\begin{cases} - \frac{i d^{4} \operatorname{acosh}{\left (\frac{e x}{d} \right )}}{8 e^{3}} + \frac{i d^{3} x}{8 e^{2} \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} - \frac{3 i d x^{3}}{8 \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} + \frac{i e^{2} x^{5}}{4 d \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} & \text{for}\: \left |{\frac{e^{2} x^{2}}{d^{2}}}\right | > 1 \\\frac{d^{4} \operatorname{asin}{\left (\frac{e x}{d} \right )}}{8 e^{3}} - \frac{d^{3} x}{8 e^{2} \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} + \frac{3 d x^{3}}{8 \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} - \frac{e^{2} x^{5}}{4 d \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} & \text{otherwise} \end{cases}\right ) + e \left (\begin{cases} - \frac{2 d^{4} \sqrt{d^{2} - e^{2} x^{2}}}{15 e^{4}} - \frac{d^{2} x^{2} \sqrt{d^{2} - e^{2} x^{2}}}{15 e^{2}} + \frac{x^{4} \sqrt{d^{2} - e^{2} x^{2}}}{5} & \text{for}\: e \neq 0 \\\frac{x^{4} \sqrt{d^{2}}}{4} & \text{otherwise} \end{cases}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**2*(e*x+d)*(-e**2*x**2+d**2)**(1/2),x)
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GIAC/XCAS [A] time = 0.333623, size = 100, normalized size = 0.76 \[ \frac{1}{8} \, d^{5} \arcsin \left (\frac{x e}{d}\right ) e^{\left (-3\right )}{\rm sign}\left (d\right ) - \frac{1}{120} \,{\left (16 \, d^{4} e^{\left (-3\right )} +{\left (15 \, d^{3} e^{\left (-2\right )} + 2 \,{\left (4 \, d^{2} e^{\left (-1\right )} - 3 \,{\left (4 \, x e + 5 \, d\right )} x\right )} x\right )} x\right )} \sqrt{-x^{2} e^{2} + d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(-e^2*x^2 + d^2)*(e*x + d)*x^2,x, algorithm="giac")
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